Thermal Engineering2D

Heat Exchanger Calculator (LMTD Method)

Calculate heat transfer rate using the LMTD (Log Mean Temperature Difference) method: Q = U × A × LMTD.

Inputs
Enter your values below
Result
Heat Transfer Rate
Enter values and click Calculate
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Formula
u × area × ((t1_hot − t2_cold) − (t2_hot − t1_cold)) ÷ log((t1_hot − t2_cold) ÷ (t2_hot − t1_cold)) ÷ 1000
Result unit: kW

Q = U × A × LMTD where LMTD = (ΔT1 − ΔT2) / ln(ΔT1/ΔT2). Counter-current flow assumed. ΔT1 = T_hot_in − T_cold_out, ΔT2 = T_hot_out − T_cold_in.

Introduction

Calculate heat transfer rate for a heat exchanger using the Log Mean Temperature Difference (LMTD) method. This calculator assumes counter-current flow and uses the standard Q = U·A·LMTD formula.

How This Calculator Works

Q = U × A × LMTD where LMTD = (ΔT1 − ΔT2) / ln(ΔT1/ΔT2). Counter-current flow assumed. ΔT1 = T_hot_in − T_cold_out, ΔT2 = T_hot_out − T_cold_in.

Step-by-step process:

  1. Enter your input values in the calculator above
  2. The engine converts all inputs to SI base units (meters, kg, Pa)
  3. The formula is evaluated: u * area * ((t1_hot - t2_cold) - (t2_hot - t1_cold)) / log((t1_hot - t2_cold) / (t2_hot - t1_cold)) / 1000
  4. Result is formatted with the appropriate unit and precision

Calculation Example

50m² exchanger, U=500 W/m²K, ΔT1=50°C (hot in−cold out), ΔT2=40°C (hot out−cold in), LMTD=44.8 → Q ≈ 1120 kW

Inputs: u=500, area=50, t1_hot=100, t2_hot=60, t1_cold=20, t2_cold=50
Result: 1120 kW

Unit Conversion for Heat Exchanger Duty

**Heat duty units**

- 1 kW = 3412 BTU/hr = 0.003412 MMBtu/hr

- 1 MMBtu/hr = 293.1 kW

- 1 W = 3.412 BTU/hr

**Temperature units**

- °F = °C × 9/5 + 32

- ΔT in °C = ΔT in K

**Area units**

- 1 m² = 10.764 ft²

Exchanger duty Q = m × cp × ΔT or Q = U × A × LMTD. Keep mass flow, specific heat, and temperature difference in one consistent unit system before computing.

Worked Example: LMTD Step by Step

Size the duty of a shell-and-tube exchanger with hot fluid 100 C in, 60 C out, and cold fluid 20 C in, 50 C out (counter-current), U = 500 W/m2K, area = 50 m2.

Step 1 - temperature differences at each end: Delta-T1 = T_hot_in - T_cold_out = 100 - 50 = 50 K. Delta-T2 = T_hot_out - T_cold_in = 60 - 20 = 40 K.

Step 2 - LMTD = (50 - 40) / ln(50/40) = 10 / 0.2231 = 44.8 K.

Step 3 - duty Q = U x A x LMTD = 500 x 50 x 44.8 = 1,120,000 W = 1120 kW.

Check the unit conversion section to express this as BTU/hr (1120 kW = 3.82 MMBtu/hr).

Typical Overall Heat Transfer Coefficients

Selecting a realistic U value is the most uncertain part of an LMTD design. Typical ranges:

| Service | U (W/m2K) |

|---|---|

| Water to water | 800 - 1500 |

| Water to oil | 100 - 350 |

| Steam to water | 1000 - 4000 |

| Steam to oil | 100 - 300 |

| Gas to gas | 10 - 60 |

| Gas to water | 30 - 100 |

| Condensing refrigerant to water | 400 - 1000 |

Use the low end of the range when fouling is expected or the service is dirty; the design U must include an allowance for fouling (typical 0.0002 - 0.0006 m2K/W fouling resistance). Verify the U against manufacturer data or Perry's Handbook for the final design.

Engineering Applications

  • Heat exchanger sizing
  • Process thermal design
  • HVAC design
  • Energy recovery

Frequently Asked Questions

What is LMTD?

Log Mean Temperature Difference accounts for the varying temperature driving force along the heat exchanger. It is the logarithmic average of the temperature differences at each end.

What is a typical U value?

For liquid-liquid exchangers: 300-1000 W/m²K. For gas-liquid: 50-300 W/m²K. For condensing/boiling: 1000-5000 W/m²K.

How do I convert heat duty between kW and MMBtu/hr?

1 kW = 3412 BTU/hr = 0.003412 MMBtu/hr. For example, 100 kW = 0.3412 MMBtu/hr. Convert to consistent units for exchanger sizing.

What is the difference between counter-current and co-current flow?

In counter-current flow the hot and cold streams enter at opposite ends, giving the largest LMTD and the smallest area for a given duty. In co-current (parallel) flow both enter at the same end; the temperature approach is limited and LMTD is lower, so more area is needed. The formula in this calculator assumes counter-current flow, which is the usual design choice for shell-and-tube exchangers.

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Engineering Disclaimer: Calculations are for reference and educational purposes only. Always verify results independently for engineering design. See full disclaimer.
Reviewed by: Industrial Engineering Team
References: ASME B31.3, ASTM A36, Perry's Chemical Engineers' Handbook