Pressure Drop Calculator (Darcy-Weisbach)
Calculate pressure drop in a pipe using the Darcy-Weisbach equation: ΔP = f × L/D × ρv²/2.
Introduction
Calculate pressure drop (head loss) in a straight pipe using the Darcy-Weisbach equation. This is the most accurate method for single-phase incompressible flow in pipes.
How This Calculator Works
Darcy-Weisbach equation: ΔP = f × (L/D) × (ρv²/2). The /1000 converts Pa to kPa. L and D are in meters (auto-converted), v in m/s, ρ in kg/m³.
Step-by-step process:
- Enter your input values in the calculator above
- The engine converts all inputs to SI base units (meters, kg, Pa)
- The formula is evaluated:
friction * length / diameter * density * velocity^2 / 2 / 1000 - Result is formatted with the appropriate unit and precision
Calculation Example
Darcy-Weisbach Equation Explained
The Darcy-Weisbach equation is the most accurate general method for pressure drop in pipes:
DeltaP = f x (L / D) x (rho x v^2 / 2)
Where DeltaP = pressure drop (Pa), f = Darcy friction factor, L = pipe length (m), D = inner diameter (m), rho = fluid density (kg/m3), v = average velocity (m/s).
Example: water (1000 kg/m3) at 2 m/s in a 100 mm pipe, 100 m long, f = 0.02: DeltaP = 0.02 x (100/0.1) x (1000 x 4 / 2) = 40,000 Pa = 40 kPa. Doubling velocity quadruples the drop because v appears squared.
Typical Friction Factors
| Pipe Condition | Darcy Friction Factor (f) |
|---|---|
| Smooth drawn tubing (copper, plastic) | 0.01 - 0.02 |
| New commercial steel | 0.015 - 0.025 |
| Slightly corroded steel | 0.02 - 0.04 |
| Heavily fouled / old pipe | 0.04 - 0.08 |
For laminar flow (Re < 2300), f = 64/Re exactly. For turbulent flow, f depends on Reynolds number and relative roughness — use the Moody chart or Colebrook equation. A 0.02 default is a reasonable first estimate for clean industrial water lines.
Worked Example: Sizing a Pump for Line Loss
A 100 m long, 100 mm ID water line carries 2 m/s (56.5 m3/h). With f = 0.02:
DeltaP = 0.02 x (100/0.1) x (1000 x 2^2 / 2) = 40 kPa
Convert to head: h = DeltaP / (rho x g) = 40,000 / (1000 x 9.81) = 4.1 m. This head loss must be added to static head when sizing the pump. A 200 m line doubles the drop to 80 kPa (8.1 m); a 50 mm line at the same velocity quadruples it to 160 kPa.
Engineering Applications
- •Piping system design
- •Pump head calculation
- •Hydraulic analysis
- •Process piping
Frequently Asked Questions
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